Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.3 - Adding and Subtracting Rational Expressions with the Same Denominator and Least Common Denominator - Exercise Set: 30

Answer

LCD=(x+1)(x+3)(x+7)

Work Step by Step

$\frac{4}{x^{2}+4x+3}$, $\frac{4x-2}{x^{2}+10x+21}$ $x^{2}$+4x+3=$x^{2}$+x+3x+3=x(x+1)+3(x+1)=(x+3)(x+1) $x^{2}$+10x+21=$x^{2}$+7x+3x+21=x(x+7)+3(x+7)=(x+3)(x+7) LCD=(x+1)(x+3)(x+7)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.