Answer
$\frac{(4x+1)y}{3y(x+2)}$
Work Step by Step
$\frac{4x+1}{3x+6}$=$\frac{4x+1}{3(x+2)}$=
$\frac{4x+1}{3(x+2)}$.1=$\frac{4x+1}{3(x+2)}$.$\frac{y}{y}$
$\frac{(4x+1)y}{3y(x+2)}$
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