Answer
The solutions are -3 and 0 and 3.
Work Step by Step
3$x^{3}$-27x=0
3x($x^{2}$-9)=0
3x(x-3)(x+3)=0
x=0 or x-3=0 or x+3=0
x=0 or x=3 or x=-3
The solutions are -3 and 0 and 3.
Check
Let x=-3
3$x^{3}$-27x=0
3$(-3)^{3}$-27(-3)=0
3(-27)-27(-3)=0
-81+81=0
0=0
Let x=3
3$x^{3}$-27x=0
3$(3)^{3}$-27(3)=0
3(27)-27(3)=0
81-81=0
0=0
Let x=0
3$x^{3}$-27x=0
3$(0)^{3}$-27(0)=0
3(0)-0=0
0-0=0
0=0
