# Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 458: 38

-3 and 0 and 3

#### Work Step by Step

4$y^{3}$-36y=0 y(4$y^{2}$-36)=0 y(2y-6)(2y+6)=0 y=0 or 2y-6=0 or 2y+6=0 y=0 or 2y-6+6=0+6 or 2y+6-6=0-6 y=0 or 2y=6 or 2y=-6 y=0 or y= $\frac{6}{2}$ or y=$\frac{-6}{2}$ y=0 or y=3 or y=-3 The solutions are 0 and 3 and -3. Check Let x=o 4$y^{3}$-36y=0 4*$0^{3}$-36*0=0 0-0=0 0=0 Let x= 3 4$y^{3}$-36y=0 4*$3^{3}$-36*3=0 4*27-108=0 108-108=0 0=0 Let x=- 3 4$y^{3}$-36y=0 4*$(-3)^{3}$-36(-3)=0 4(-27)+108=0 -108+108=0 0=0

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