Answer
The solutions are -1 and 3.
Work Step by Step
3$x^{2}$-6x-9=0
3$x^{2}$+3x-9x-9=0
3x(x+1)-9(x+1)=0
(3x-9)(x+1)=0
3x-9 =0 or x+1=0
3x=9 0r x=-1
x=3 or x=-1
The solutions are -1 and 3.
Check
Let x=-1
3$x^{2}$-6x-9=0
3$(-1)^{2}$-6(-1)-9=0
3+6-9=0
9-9=0
0=0
Let x=3
3$x^{2}$-6x-9=0
3$(3)^{2}$-6(3)-9=0
3*9-18-9=0
27-18-9=0
0=0
3+6-9=0
9-9=0
0=0
