Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 458: 62

Answer

The solutions are 0 and $\frac{3}{2}$.

Work Step by Step

9y=6$y^{2}$ 9y-9y=6$y^{2}$-9y 0=6$y^{2}$-9y or 6$y^{2}$-9y=0 3y(2y-3)=0 y=0 or 2y-3=0 y=0 or 2y=3 y=0 or y=$\frac{3}{2}$ The solutions are 0 and $\frac{3}{2}$. Check Let x=o 9y=6$y^{2}$ 9*0=6*$0^{2}$ 0=0 Let x=$\frac{3}{2}$ 9y=6$y^{2}$ 9$\frac{3}{2}$=6$(3/2)^{2}$ $\frac{27}{2}$=6$\frac{9}{4}$ $\frac{27}{2}$=$\frac{54}{4}$ $\frac{27}{2}$=$\frac{27}{2}$
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