Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 458: 40


The solution is $\frac{3}{10}$.

Work Step by Step

5(3-4x)=9 15-20x=9 15-20x-9=9-9 6-20x=0 2(3-10x)=0 3-10x=0 3-10x-3=0-3 -10x=-3 10x=3 $\frac{10x}{10}$=$\frac{3}{10}$ x=$\frac{3}{10}$ The solution is $\frac{3}{10}$. Check Let x=$\frac{3}{10}$ 5(3-4x)=9 5(3-4*$\frac{3}{10}$)=9 5(3-$\frac{12}{10}$)=9 5*3-5*$\frac{12}{10}$)=9 15-6=9 9=9
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