Answer
The solutions are 2 and - $\frac{4}{5}$.
Work Step by Step
5$x^{2}$-6x-8=0
5$x^{2}$-6x-8=0
5$x^{2}$+4x-10x-8=0
x(5x+4)-2(5x+4)=0
(x-2)(5x+4)=0
x-2 =0 or 5x+4=0
x=2 0r x=-$\frac{4}{5}$
The solutions are 2 and - $\frac{4}{5}$.
Check
Let x=- $\frac{4}{5}$
5$x^{2}$-6x-8=0
5$(-4/5)^{2}$-6$\frac{-4}{5}$-8=0
5*16/25+$\frac{24}{5}$-8=0
1*16/5+$\frac{24}{5}$-8=0
16/5+$\frac{24}{5}$-8=0
$\frac{40}{5}$-8=0
8-8=0
0=0
Let x=2
5$x^{2}$-6x-8=0
5*4-6*2-8=0
20-12-8=0
20-20=0
0=0