Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 458: 36

Answer

$x=\frac{3}{4}$ or $x=-\frac{7}{9}$

Work Step by Step

We simplify as follows: $36x^{2}+x-21=0$ $36x^{2}+28x-27x-21=0$ $4x(9x+7)-3(9x+7)=0$ $(4x-3)(9x+7)=0$ $4x-3=0$ or $9x+7=0$ $4x=3$ or $9x=-7$ $x=\frac{3}{4}$ or $x=-\frac{7}{9}$
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