Answer
The solutions are $\frac{-1}{4}$ and 3.
Work Step by Step
x(4x-11)=3
4$x^{2}$-11x=3
4$x^{2}$-11x-3=3-3
4$x^{2}$-11x-3=0
4$x^{2}$-12x+1x-3=0
4x(x-3)+1(x-3)=0
(4x+1)(x-3)=0
4x+1=0 x-3=0
4x+1-1=0-1 or x-3+3=0+3
4x=-1 or x=3
$\frac{4x}{4}$ =$\frac{-1}{4}$ or x=3
x=$\frac{-1}{4}$ or x=3
The solutions are $\frac{-1}{4}$ and 3.
Check
Let x=-$\frac{1}{4}$
x(4x-11)=3
-$\frac{1}{4}$[-$\frac{1}{4}$4-11]=3
-$\frac{1}{4}$(-1-11)=3
-$\frac{1}{4}$(-12)=3
3=3
Let x=3
x(4x-11)=3
3(4*3-11)=3
3(12-11)=3
3*1=3
3=3
