Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set: 16

Answer

The solutions are -$\frac{2}{9}$ and $\frac{1}{4}$.

Work Step by Step

(x+$\frac{2}{9}$)(x-$\frac{1}{4}$)=0 x-$\frac{1}{4}$ =0 or x+$\frac{2}{9}$=0 x-$\frac{1}{4}$+$\frac{1}{4}$ =0 +$\frac{1}{4}$ or x+$\frac{2}{9}$-$\frac{2}{9}$=0-$\frac{2}{9}$ x=-$\frac{2}{9}$ or x=$\frac{1}{4}$ The solutions are -$\frac{2}{9}$ and $\frac{1}{4}$. check $\frac{1}{4}$ (x+$\frac{2}{9}$)(x-$\frac{1}{4}$)=0 ($\frac{1}{4}$+$\frac{2}{9}$)($\frac{1}{4}$-$\frac{1}{4}$)=0 ($\frac{1}{4}$+$\frac{2}{9}$)0=0 0=0 Let x= $\frac{-2}{9}$ (x+$\frac{2}{9}$)(x-$\frac{1}{4}$)=0 ($\frac{-2}{9}$ +$\frac{2}{9}$)($\frac{-2}{9}$ -$\frac{1}{4}$)=0 0($\frac{-2}{9}$ -$\frac{1}{4}$)=0 0=0
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