Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 457: 19

Answer

The solutions are 4 and 9.

Work Step by Step

$x^{2}$-13x+36=0 $x^{2}$-9x-4x+36=0 x(x-9)-4(x-9)=0 (x-4)(x-9)=0 x-4=0 or x-9=0 x-4+4=0+4 or x-9+9=0+9 x=4 or x=9 The solutions are 4 and 9. Check Let x=4 (x-4)(x-9)=0 (4-4)(4-9)=0 0(-5)=0 0=0 Let x=9 (x-4)(x-9)=0 (9-4)(9-9)=0 5*0=0 0=0
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