Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set: 22

Answer

The solutions are 2 and 3.

Work Step by Step

$x^{2}$-5x+6=0 $x^{2}$-2x-3x+6=0 x(x-2)-3(x-2)=0 (x-3)(x-2)=0 x-3=0 or x-2=0 x-3+3=0+3 or x-2+2=0+2 x=3 or x=2 The solutions are 2 and 3. Check Let x=2 $x^{2}$-5x+6=0 $2^{2}$ -5*2+6=0 4-10+6=0 -6+6=0 0=0 Let x=3 $x^{2}$-5x+6=0 $3^{2}$ -5(3)+6=0 9-15+6=0 0=0
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