Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 457: 27

Answer

The solutions are -4 and 4.

Work Step by Step

$x^{2}$=16 $x^{2}$-16=16-16 $x^{2}$-16=0 $x^{2}$-$4^{2}$=0 (x+4)(x-4)=0 x+4=0 or x-4=0 x+4-4=0-4 or x-4+4=0+4 x=-4 or x=4 The solutions are -4 and 4. Check Let x=-4 $x^{2}$=16 $(-4)^{2}$ =16 16=16 Let x=4 $x^{2}$=16 $4^{2}$ =16 16=16 0=0
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