Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set: 28


The solutions are -3 and 3.

Work Step by Step

$x^{2}$=9 $x^{2}$-9=9-9 $x^{2}$-9=0 $x^{2}$-$3^{2}$=0 (x+3)(x-3)=0 x+3=0 or x-3=0 x+3-3=0-3 or x-3+3=0+3 x=-3 or x=3 The solutions are -3 and 3. Check Let x=-3 $x^{2}$=9 $(-3)^{2}$ =9 9=9 Let x=3 $x^{2}$=9 $3^{2}$ =9 9=9 0=0
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