Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set - Page 448: 81

Answer

The solution is -$\frac{1}{3}$.

Work Step by Step

3x+1=0 3x+1-1=0-1 3x=-1 $\frac{3x}{3}$=$\frac{-1}{3}$ x=-$\frac{1}{3}$ check 3x+1=0 3(-$\frac{1}{3}$)+1=0 -1+1=0 0=0
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