Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set: 69

Answer

$(x^2-y)(x^4 +x^2y + y^2) $

Work Step by Step

$x^6 + y^3 = (x^2)^3 - y^3 =(x^2-y)((x^2)^2 +x^2y + y^2) = (x^2-y)(x^4 +x^2y + y^2) $
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