Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set: 66

Answer

a(2b+3a)($4b^{2}$ -6ab+9$a^{2}$)

Work Step by Step

8a$b^{3}$+27$a^{4}$=a(8$b^{3}$+27$a^{3}$ )=a[ $(2b)^{3}$ +$(3a)^{3}$]= a[(2b+3a)($(2b)^{2}$ -(2b)(3a)+$(3a)^{2}$)]= a[(2b+3a)($4b^{2}$ -6ab+9$a^{2}$)
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