Answer
$(2x+3y)(4x^2-6xy+9y^2)$
Work Step by Step
$m^3+n^3 =(m+n)(m^2-mn+n^2)$
$8x^3+27y^3$
$2^3x^3+3^3y^3$
$m=2x$, $n=3y$
$8x^3+27y^3$
$8x^3+27y^3 = (2x+3y)((2x)^2-2x*3y+(3y)^2)$
$8x^3+27y^3 = (2x+3y)(4x^2-6xy+9y^2)$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set - Page 448: 71
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