Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set: 56

Answer

$ (n - 2)(n+2)(n^2+4)$

Work Step by Step

$n^4 - 16 = (n^2)^2 - 4^2 = (n^2 - 4)(n^2 + 4) = ((n)^2 - 2^2)(n^2 + 4) = (n - 2)(n+2)(n^2+4)$
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