Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set - Page 448: 74



Work Step by Step

$x^{3}$-8=$x^{3}$-$2^{3}$=(x-2)($x^{2}$+2x+$2^{2}$)= (x-2)($x^{2}$+2x+4)
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