Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.5 - Factoring by Special Products - Exercise Set - Page 448: 61

Answer

$(m+n)(m^2-mn+n^2)$

Work Step by Step

$m^3+n^3$ $x=m$, $y=n$ $x^3+y^3 = (x+y)(x^2-xy+y^2)$ $m^3+n^3$ $m^3+n^3 = (m+n)(m^2-mn+n^2)$
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