Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Practice - Page 386: 9

Answer

$x^{2}-81$

Work Step by Step

Step 1: $(x+9)(x-9)$ Step 2: Using a special product to multiply, $(x+9)(x-9)=(x)^{2}-(9)^{2}$ Step 3: $(x)^{2}-(9)^{2}=x^{2}-81$
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