Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Practice - Page 386: 12

Answer

$9a^{2}-b^{2}$

Work Step by Step

Step 1: $(3a-b)(3a+b)$ Step 2: Using a special product to multiply, $(3a-b)(3a+b)=(3a)^{2}-(b)^{2}$ Step 3: $(3a)^{2}-(b)^{2}=9a^{2}-b^{2}$
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