Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Practice - Page 386: 12



Work Step by Step

Step 1: $(3a-b)(3a+b)$ Step 2: Using a special product to multiply, $(3a-b)(3a+b)=(3a)^{2}-(b)^{2}$ Step 3: $(3a)^{2}-(b)^{2}=9a^{2}-b^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.