## Algebra: A Combined Approach (4th Edition)

$x^{2}-\frac{1}{9}$
Step 1: Using the special product to multiply, $(x-\frac{1}{3})(x+\frac{1}{3)})=(x)^{2}-(\frac{1}{3})^{2}$ Step 2: $(x)^{2}-(\frac{1}{3})^{2}= x^{2}-\frac{1}{9}$