Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Practice: 15

Answer

$10y^{2}-19y-15$

Work Step by Step

Step 1: A Special Product cannot be applied here. In its place, we will use the FOIL method. Step 2: $(5y+3)(2y-5)=5y(2y)+5y(-5)+3(2y)+3(-5)$ Step 3: $5y(2y)+5y(-5)+3(2y)+3(-5)=10y^{2}-25y+6y-15$ Step 4: $10y^{2}-25y+6y-15=10y^{2}-19y-15$ Step 5: Therefore, the required expression is $10y^{2}-19y-15$
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