Answer
$25y^{2}-\frac{10y}{9}+\frac{1}{81}$
Work Step by Step
Step 1: Using the special product,
$(5y-\frac{1}{9})^{2}=(5y)^{2}-2(5y)(\frac{1}{9})+(\frac{1}{9})^{2}$
Step 2: $(5y)^{2}-2(5y)(\frac{1}{9})+(\frac{1}{9})^{2}=25y^{2}-\frac{10y}{9}+\frac{1}{81}$
