Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Practice: 17

Answer

$25y^{2}-\frac{10y}{9}+\frac{1}{81}$

Work Step by Step

Step 1: Using the special product, $(5y-\frac{1}{9})^{2}=(5y)^{2}-2(5y)(\frac{1}{9})+(\frac{1}{9})^{2}$ Step 2: $(5y)^{2}-2(5y)(\frac{1}{9})+(\frac{1}{9})^{2}=25y^{2}-\frac{10y}{9}+\frac{1}{81}$
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