Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Practice - Page 386: 14

Answer

$49x^{2}-14x+1$

Work Step by Step

Step 1: Using the special product, $(7x-1)^{2}=(7x)^{2}+2(7x)(-1)+(1)^{2}$ Step 2: $(7x)^{2}+2(7x)(-1)+(1)^{2}=49x^{2}-14x+1$
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