Answer
$4a^{2}-1$
Work Step by Step
Step 1: $(2a−1)(2a+1)$
Step 2: Using a special product to multiply, $(2a−1)(2a+1)=(2a)^{2}-(1)^{2}$
Step 3: $(2a)^{2}-(1)^{2}=4a^{2}-1$
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