Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 896: 8



Work Step by Step

$e^{2x}=8$ Apply $\ln$ to both sides of the equation: $\ln e^{2x}=\ln8$ Take $2x$ down to multiply in front of its respective $\ln$: $2x\ln e=\ln8$ Since $\ln e=1$, this equation simplifies to: $2x=\ln8$ Solve for $x$: $x=\dfrac{\ln8}{2}\approx1.0397$
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