## Algebra: A Combined Approach (4th Edition)

$x=\dfrac{5}{8}$
$\log_{4}10-\log_{4}x=2$ Combine $\log_{4}10-\log_{4}x$ as the $\log$ of a division: $\log_{4}\dfrac{10}{x}=2$ Rewrite this equation in exponential form: $4^{2}=\dfrac{10}{x}$ $\dfrac{10}{x}=16$ Solve for $x$: $\dfrac{x}{10}=\dfrac{1}{16}$ $x=\dfrac{10}{16}$ $x=\dfrac{5}{8}$