Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 896: 11



Work Step by Step

$4^{x+7}=3$ Apply $\log$ to both sides of the equation: $\log4^{x+7}=\log3$ Take $x+7$ down to multiply in front of its respective $\log$: $(x+7)\log4=\log3$ Solve for $x$: $x+7=\dfrac{\log3}{\log4}$ $x=\dfrac{\log3}{\log4}-7\approx-6.2075$
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