## Algebra: A Combined Approach (4th Edition)

$x=\dfrac{1}{8}$
$\log_{5}(x+3)-\log_{5}x=2$ Combine $\log_{5}(x+3)-\log_{5}x$ as the $\log$ of a division: $\log_{5}\dfrac{x+3}{x}=2$ Rewrite in exponential form: $5^{2}=\dfrac{x+3}{x}$ $\dfrac{x+3}{x}=25$ Take $x$ to multiply the right side of the equation: $x+3=25x$ Solve for $x$: $x-25x=-3$ $-24x=-3$ $x=\dfrac{-3}{-24}$ $x=\dfrac{1}{8}$