Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set: 17

Answer

{$\frac{1}{2}$}

Work Step by Step

$\log_{4} 2+\log_{4} x=0$ $\log_{4} (2\times x)=0$ $\log_{4} (2x)=0$ $2x=4^{0}$ $2x=1$ $x=\frac{1}{2}$ Checking the answer by inserting it in $\log_{4} (2x)=0$: $\log_{4} (2\times\frac{1}{2})=0$ $\log_{4} (1)=0$ $\log_{4} 4^{0}=0$ $0\log_{4} 4=0$ $0=0$ Therefore, the solution set is {$\frac{1}{2}$}.
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