Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 896: 12



Work Step by Step

$6^{x+3}=2$ Apply $\log$ to both sides of the equation: $\log6^{x+3}=\log2$ Take $x+3$ down to multiply in front of its respective $\log$: $(x+3)\log6=\log2$ Solve for $x$: $x+3=\dfrac{\log2}{\log6}$ $x=\dfrac{\log2}{\log6}-3\approx-2.6131$
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