Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 896: 18



Work Step by Step

$\log_{3} 5+\log_{3} x=1$ $\log_{3} (5\times x)=1$ $\log_{3} (5x)=1$ $5x=3^{1}$ $5x=3$ $x=\frac{3}{5}$ Checking the answer by inserting it in $\log_{3} (5x)=1$: $\log_{3} (5\times\frac{3}{5})=1$ $\log_{3} (3)=1$ $\log_{3} 3^{1}=1$ $1\log_{3} 3=1$ $1=1$ Therefore, the solution set is {$\frac{3}{5}$}.
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