Answer
$\log_3y-\log_3(y+2)+\log_3(y^3+11)=\log_3\frac{y^4+11y}{y+2}$
Work Step by Step
$\log_3y-\log_3(y+2)+\log_3(y^3+11)$
$=\log_3\frac{y}{y+2}+\log_3(y^3+11)$
$=\log_3\frac{y(y^3+11)}{y+2}$
$=\log_3\frac{y^4+11y}{y+2}$
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