Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.6 - Integrated Review - Functions and Properties of Logarithms: 25

Answer

$x=\dfrac{1}{2}$

Work Step by Step

$\log_{49}7=x$ Rewrite in exponential form: $49^{x}=7$ Rewrite $49$ as $7^{2}$: $(7^{2})^{x}=7$ Multiply the exponents on the left side of the equation: $7^{2x}=7$ If $7^{2x}=7$, then $2x=1$: $2x=1$ Solve for $x$: $x=\dfrac{1}{2}$
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