## Algebra: A Combined Approach (4th Edition)

$x=\dfrac{1}{2}$
$\log_{49}7=x$ Rewrite in exponential form: $49^{x}=7$ Rewrite $49$ as $7^{2}$: $(7^{2})^{x}=7$ Multiply the exponents on the left side of the equation: $7^{2x}=7$ If $7^{2x}=7$, then $2x=1$: $2x=1$ Solve for $x$: $x=\dfrac{1}{2}$