## Algebra: A Combined Approach (4th Edition)

$x\log_{2}5+\log_{2}8=\log_{2}(8\cdot5^{x})$
$x\log_{2}5+\log_{2}8$ Take the $x$ multiplying in front of $\log_{2}5$ inside as an exponent: $x\log_{2}5+\log_{2}8=\log_{2}5^{x}+\log_{2}8=...$ Combine $\log_{2}5^{x}+\log_{2}8$ as the $\log$ of a product: $...=\log_{2}(8\cdot5^{x})$