# Chapter 12 - Section 12.6 - Integrated Review - Functions and Properties of Logarithms - Page 884: 31

$x\log_{2}5+\log_{2}8=\log_{2}(8\cdot5^{x})$

#### Work Step by Step

$x\log_{2}5+\log_{2}8$ Take the $x$ multiplying in front of $\log_{2}5$ inside as an exponent: $x\log_{2}5+\log_{2}8=\log_{2}5^{x}+\log_{2}8=...$ Combine $\log_{2}5^{x}+\log_{2}8$ as the $\log$ of a product: $...=\log_{2}(8\cdot5^{x})$

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