#### Answer

$x=2$

#### Work Step by Step

$\log_{4}16=x$
Rewrite in exponential form:
$4^{x}=16$
Transform $16$ into $4^{2}$:
$4^{x}=4^{2}$
If $4^{x}=4^{2}$, then $x=2$
$x=2$ is the solution to this equation:

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$x=2$

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