Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.6 - Integrated Review - Functions and Properties of Logarithms - Page 884: 24



Work Step by Step

$\log_{4}16=x$ Rewrite in exponential form: $4^{x}=16$ Transform $16$ into $4^{2}$: $4^{x}=4^{2}$ If $4^{x}=4^{2}$, then $x=2$ $x=2$ is the solution to this equation:
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