## Algebra: A Combined Approach (4th Edition)

$x=2$
$\log_{4}16=x$ Rewrite in exponential form: $4^{x}=16$ Transform $16$ into $4^{2}$: $4^{x}=4^{2}$ If $4^{x}=4^{2}$, then $x=2$ $x=2$ is the solution to this equation: