## Algebra: A Combined Approach (4th Edition)

$x=5$
$\log_{x}\dfrac{1}{125}=-3$ Rewrite in exponential form: $x^{-3}=\dfrac{1}{125}$ Rewrite $x^{-3}$ as $\dfrac{1}{x^{3}}$: $\dfrac{1}{x^{3}}=\dfrac{1}{125}$ If $\dfrac{1}{x^{3}}=\dfrac{1}{125}$, then $x^{3}=125$ $x^{3}=125$ Take the cubic root of both sides of the equation: $\sqrt[3]{x^{3}}=\sqrt[3]{125}$ $x=5$