Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.6 - Integrated Review - Functions and Properties of Logarithms - Page 884: 29

Answer

$x=\dfrac{1}{9}$

Work Step by Step

$\log_{3}x=-2$ Rewrite in exponential form: $3^{-2}=x$ Rewrite $3^{-2}$ as $\dfrac{1}{3^{2}}$: $x=\dfrac{1}{3^{2}}$ $x=\dfrac{1}{9}$
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