Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.2 - Rational Exponents - Exercise Set - Page 694: 86


$\sqrt[15] {64a^{3}b^{5}}$

Work Step by Step

$\sqrt[3] b\sqrt[5] {4a}=b^{1/3}(4a)^{1/5}=b^{5/15}(4a)^{3/15}=(b^{5}(4a)^{3})^{1/15}=\sqrt[15] {64a^{3}b^{5}}$
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