Answer
$\sqrt[4] 2y$
Work Step by Step
$\sqrt[8] {4y^{2}}=(4y^{2})^{1/8}=2^{2/8}y^{2/8}=(\sqrt[8] {2y})^{2}=\sqrt[4] 2y$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Section 10.2 - Rational Exponents - Exercise Set - Page 694: 66
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