#### Answer

$\sqrt[4] 2y$

#### Work Step by Step

$\sqrt[8] {4y^{2}}=(4y^{2})^{1/8}=2^{2/8}y^{2/8}=(\sqrt[8] {2y})^{2}=\sqrt[4] 2y$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$\sqrt[4] 2y$

$\sqrt[8] {4y^{2}}=(4y^{2})^{1/8}=2^{2/8}y^{2/8}=(\sqrt[8] {2y})^{2}=\sqrt[4] 2y$

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