Answer
$\sqrt[15] {343y^{5}}$
Work Step by Step
$\sqrt[5] 7\sqrt[3] y=7^{1/5}y^{1/3}=7^{3/15}y^{5/15}=(7^{3}y^{5})^{1/15}=(343y^{5})^{1/15}=\sqrt[15] {343y^{5}}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Section 10.2 - Rational Exponents - Exercise Set - Page 694: 83
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