## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 10 - Section 10.2 - Rational Exponents - Exercise Set - Page 694: 58

#### Answer

$\dfrac{(m^{2}n)^{1/4}}{m^{-1/2}n^{5/8}}=\dfrac{m}{n^{3/8}}$

#### Work Step by Step

$\dfrac{(m^{2}n)^{1/4}}{m^{-1/2}n^{5/8}}$ Evaluate the power indicated in the numerator: $\dfrac{(m^{2}n)^{1/4}}{m^{-1/2}n^{5/8}}=\dfrac{m^{1/2}n^{1/4}}{m^{-1/2}n^{5/8}}=...$ Evaluate the division. Give the answer without negative exponents: $...=m^{1/2+1/2}n^{1/4-5/8}=mn^{-3/8}=\dfrac{m}{n^{3/8}}$

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