Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.2 - Rational Exponents - Exercise Set - Page 694: 65


$2\sqrt x$

Work Step by Step

$\sqrt[4] {16x^{2}}=(16x^{2})^{1/4}=16^{1/4}(x^{2})^{1/4}=4^{2/4}x^{2/4}=(4x)^{1/2}=\sqrt {4x}=2\sqrt x$
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