Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.2 - Rational Exponents - Exercise Set: 59

Answer

$\dfrac{(x^{3}y^{2})^{1/4}}{(x^{-5}y^{-1})^{-1/2}}=\dfrac{1}{x^{7/4}}$

Work Step by Step

$\dfrac{(x^{3}y^{2})^{1/4}}{(x^{-5}y^{-1})^{-1/2}}$ Evaluate the powers indicated in the numerator and in the denominator: $\dfrac{(x^{3}y^{2})^{1/4}}{(x^{-5}y^{-1})^{-1/2}}=\dfrac{x^{3/4}y^{1/2}}{x^{5/2}y^{1/2}}=...$ Evaluate the division. Give the answer without negative exponents: $...=x^{3/4-5/2}y^{1/2-1/2}=x^{-7/4}=\dfrac{1}{x^{7/4}}$
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