Answer
$\dfrac{(x^{3}y^{2})^{1/4}}{(x^{-5}y^{-1})^{-1/2}}=\dfrac{1}{x^{7/4}}$
Work Step by Step
$\dfrac{(x^{3}y^{2})^{1/4}}{(x^{-5}y^{-1})^{-1/2}}$
Evaluate the powers indicated in the numerator and in the denominator:
$\dfrac{(x^{3}y^{2})^{1/4}}{(x^{-5}y^{-1})^{-1/2}}=\dfrac{x^{3/4}y^{1/2}}{x^{5/2}y^{1/2}}=...$
Evaluate the division. Give the answer without negative exponents:
$...=x^{3/4-5/2}y^{1/2-1/2}=x^{-7/4}=\dfrac{1}{x^{7/4}}$
