## Algebra: A Combined Approach (4th Edition)

$\dfrac{(x^{3}y^{2})^{1/4}}{(x^{-5}y^{-1})^{-1/2}}=\dfrac{1}{x^{7/4}}$
$\dfrac{(x^{3}y^{2})^{1/4}}{(x^{-5}y^{-1})^{-1/2}}$ Evaluate the powers indicated in the numerator and in the denominator: $\dfrac{(x^{3}y^{2})^{1/4}}{(x^{-5}y^{-1})^{-1/2}}=\dfrac{x^{3/4}y^{1/2}}{x^{5/2}y^{1/2}}=...$ Evaluate the division. Give the answer without negative exponents: $...=x^{3/4-5/2}y^{1/2-1/2}=x^{-7/4}=\dfrac{1}{x^{7/4}}$