Answer
$\dfrac{(y^{3}z)^{1/6}}{y^{-1/2}z^{1/3}}=\dfrac{y}{z^{1/6}}$
Work Step by Step
$\dfrac{(y^{3}z)^{1/6}}{y^{-1/2}z^{1/3}}$
Evaluate the power indicated in the numerator:
$\dfrac{(y^{3}z)^{1/6}}{y^{-1/2}z^{1/3}}=\dfrac{y^{1/2}z^{1/6}}{y^{-1/2}z^{1/3}}=...$
Evaluate the division and write the answer without negative exponents:
$...=y^{1/2+1/2}z^{1/6-1/3}=yz^{-1/6}=\dfrac{y}{z^{1/6}}$
