## Algebra: A Combined Approach (4th Edition)

$2+3[10(4\cdot5-16)-30]=32$
$2+3[10(4\cdot5-16)-30]$ Inside the parentheses, evaluate the product first and after that, the substraction: $2+3[10(4\cdot5-16)-30]=2+3[10(20-16)-30]=...$ $...=2+3[10(4)-30]=...$ Now, inside the brackets, also evaluate the product first and after that, the substraction: $...=2+3[40-30]=2+3(10)=...$ Finally, evaluate the product and then the sum: $...=2+30=32$